Hi,
With an HTML form I'm able of submit a form by specifying the properties: action and method=post.
<form id="form1" runat="server" action="https://url..." method="post">....<input type="submit" value="Send"/>
But when I try to do this with a third party form (ASPxFormLayout) and an asp button with the property PostBackUrl, it doesn't work, the button redirects to the new page but does not take the form values.
I also tried it with a server side click event:
Response.Clear();
Response.ContentType = "application/x-www-form-urlencoded";
Response.Redirect("https://url...");
But the destination url receives this as a GET request, not a POST.
I need to perform several actions before submit the form, that's why I need access to the server side and then perfo ...
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