RegularExpression For Date

Hey,

I think you might try this :
(0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])[- /.](19|20)\d\d

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this will be wrong in case of feb and leap year. and also in case eof year 1800 and so on...
for 1800 we can add 18 as 18|19|20 but what will be the solution for other problem.
one more problem is there that if the number of days in the month are 31 then its fine other wise it will return wrong result too.

Thanks & Regards
Lakhan Pal Garg

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var dt;
var datesplit;
dt=year+"/"+month+"/"+day;
var entereddate=new Date(dt);
datesplit=dt.split("/");
if(entereddate.getMonth()!=datesplit[1]-1 || entereddate.getDate()!=datesplit[2] ||entereddate.getFullYear()!=datesplit[0])
{
alert('wrong date');
return false;
}


simply pass your date value(year , month and date) this will solve your problem 100%

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