open file dailog control (win forms)

Posted by Kishore under C# on 3/7/2010 | Views : 2794 | Status : [Member] | Replies : 2

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hi guys,

i created a form that contains one textbox and one button control, when i click the button a open file dialog box will be opened and the selected file name will be displayed in textbox. i know one logic ie

system.io.path.getfilename(openfiledialog1.filename);

but it displays the file extension also, i want only the file name plz help?

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Posted by: Abhi2434 on: 3/7/2010 [Member] [Microsoft_MVP] [MVP] Silver

0	You have to use string filename = System.IO.Path.GetFileName(openfiledialog1.FileName); filename = filename.Substring(0, filename.LastIndexOf('.')); the filename will hold the name of the file without extension.. Cheers. www.abhisheksur.com Kishore, if this helps please login to Mark As Answer. \| Alert Moderator

Posted by: Sagarp on: 3/26/2010 [Member] Bronze

0	Hii friend Check following Article http://www.geekpedia.com/tutorial67_Using-OpenFileDialog-to-open-files.html Thanks SagarP http://www.emanonsolutions.net http://emanonsolutions.blogspot.com/ Kishore, if this helps please login to Mark As Answer. \| Alert Moderator

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