How to change PropertiesName dynamically [Resolved]

Posted by Santosh4u under C# on 2/24/2016 | Points: 10 | Views : 1496 | Status : [Member] | Replies : 2

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Hi
how do i set properties name dynamically.

public sealed class CompanyDetails
{

string _Jan = string.Empty;
string _Feb = string.Empty;
string _Mar = string.Empty;
public string Jan { get { return _Jan; } set { _Jan = value; } }
public string Feb { get { return _Feb; } set { _Feb = value; } }
public string Mar { get { return _Mar; } set { _Mar = value; } }
}
based on passing year the propertyname should change, if passing 2016 then "jan" propertyname should be "Jan2016" same as feb and march.

Thanks

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Posted by: Rajnilari2015 on: 2/24/2016 [Member] [Microsoft_MVP] [MVP] Platinum | Points: 50

0	@Santosh4u, Try this ( just an example for demonstration) - using Dictionary Object using System.Collections.Generic; namespace ConsoleApplication1 { class DynamicProperties { Dictionary<string, object> properties = new Dictionary<string, object>(); public object this[string name] { get { if (properties.ContainsKey(name)) { return properties[name]; } return null; } set { properties[name] = value; } } } class Program { static void Main(string[] args) { int year = 2015; int month = 3; var year_MnthProperty = new DynamicProperties(); //set the property names with values switch (month) { case 1: year_MnthProperty[string.Concat(GetMonthName(month), year)] = 100; break; case 2: year_MnthProperty[string.Concat(GetMonthName(month), year)] = 200; break; case 3: year_MnthProperty[string.Concat(GetMonthName(month), year)] = 300; break; case 4: year_MnthProperty[string.Concat(GetMonthName(month), year)] = 400; break; case 5: year_MnthProperty[string.Concat(GetMonthName(month), year)] = 500; break; case 6: year_MnthProperty[string.Concat(GetMonthName(month), year)] = 600; break; } //read the property values var propertyName = string.Concat(GetMonthName(month), year); var propertyValues = year_MnthProperty[string.Concat(GetMonthName(month), year)]; } private static string GetMonthName(int month) { string monthName = string.Empty; switch(month) { case 1: monthName = "January"; break; case 2: monthName = "February"; break; case 3: monthName = "March"; break; case 4: monthName = "April"; break; case 5: monthName = "May"; break; case 6: monthName = "June"; break; } return monthName; } } } Other option should be Expando Object ( http://www.codeproject.com/Articles/121472/An-introduction-to-Expando-Object-Dotnet ) Hope this helps -- Thanks & Regards, RNA Team Santosh4u, if this helps please login to Mark As Answer. \| Alert Moderator

@Santosh4u,
Try this ( just an example for demonstration) - using Dictionary Object

using System.Collections.Generic;

namespace ConsoleApplication1
{

    class DynamicProperties
    {
        Dictionary<string, object> properties = new Dictionary<string, object>();

        public object this[string name]
        {
            get
            {
                if (properties.ContainsKey(name))
                {
                    return properties[name];
                }
                return null;
            }
            set
            {
                properties[name] = value;
            }
        }

    }    

    class Program
    {
        static void Main(string[] args)
        {
            int year = 2015;
            int month = 3;

            var year_MnthProperty = new DynamicProperties();

            //set the property names with values
            switch (month)
            {
                case 1:
                    year_MnthProperty[string.Concat(GetMonthName(month), year)] = 100; break;
                case 2:
                    year_MnthProperty[string.Concat(GetMonthName(month), year)] = 200; break;
                case 3:
                    year_MnthProperty[string.Concat(GetMonthName(month), year)] = 300; break;
                case 4:
                    year_MnthProperty[string.Concat(GetMonthName(month), year)] = 400; break;
                case 5:
                    year_MnthProperty[string.Concat(GetMonthName(month), year)] = 500; break;
                case 6:
                    year_MnthProperty[string.Concat(GetMonthName(month), year)] = 600; break;
            }

            //read the property values
            var propertyName = string.Concat(GetMonthName(month), year);
            var propertyValues = year_MnthProperty[string.Concat(GetMonthName(month), year)];
        }

        private static string GetMonthName(int month)
        {
            string monthName = string.Empty;
            switch(month)
            {
                case 1:
                    monthName = "January"; break;
                case 2:
                    monthName = "February"; break;
                case 3:
                    monthName = "March"; break;
                case 4:
                    monthName = "April"; break;
                case 5:
                    monthName = "May"; break;
                case 6:
                    monthName = "June"; break;
            }
            return monthName;
        }
    }
}

Other option should be Expando Object ( http://www.codeproject.com/Articles/121472/An-introduction-to-Expando-Object-Dotnet )

Hope this helps

--
Thanks & Regards,
RNA Team

Santosh4u, if this helps please login to Mark As Answer. | Alert Moderator

Posted by: Amatya on: 2/24/2016 [Member] Silver | Points: 25

0	Simple and good.. Nice code @Rajni Feel free to share informations. mail Id ' adityagupta200@gmail.com Thanks Santosh4u, if this helps please login to Mark As Answer. \| Alert Moderator

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