how can i take link butoon under each record in gridview

Posted by Chanti444 under ASP.NET on 12/16/2011 | Points: 10 | Views : 1776 | Status : [Member] | Replies : 3

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hi,

i designed gridview that contains user information details.here my requirement is each record first column inserted with link butoon and when i click on link button at the time i need to open separate page with edit that record can u help how can i take link butoon under each one record ........

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Posted by: Hmanjarawala on: 12/16/2011 [Member] Bronze | Points: 25

0	Hi, You can do this by adding Template column in GridView <TemplateColumn> <ItemTemplate> <asp:LinkButton: id="<urID" runat="server" /> </ItemTemplate> </TemplateColumn> Himanshu Manjarawala Sr. Software Engineer@AutomationAnywhere http://fieredotnet.wordpress.com/ Chanti444, if this helps please login to Mark As Answer. \| Alert Moderator

Posted by: Varung on: 12/16/2011 [Member] Starter | Points: 25

0	in aspx page: <asp:GridView ID="gvinsert" runat="server" onrowcommand="gvinsert_RowCommand" onselectedindexchanged="gvinsert_SelectedIndexChanged"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:LinkButton ID="lnkedit" Text="edit record" CommandName="recordedit" CommandArgument='<%# Container.DataItemIndex %>' runat="server"></asp:LinkButton> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> in .cs file protected void gvinsert_RowCommand(object sender, GridViewCommandEventArgs e) { int index =Convert.ToInt32(e.CommandArgument); if (e.CommandName == "recordedit") { //write your code here } } G.Varun Chanti444, if this helps please login to Mark As Answer. \| Alert Moderator

in aspx page:

<asp:GridView ID="gvinsert" runat="server" onrowcommand="gvinsert_RowCommand" 

			onselectedindexchanged="gvinsert_SelectedIndexChanged">

    <Columns>

    <asp:TemplateField>

    <ItemTemplate>

    <asp:LinkButton ID="lnkedit" Text="edit record" CommandName="recordedit" CommandArgument='<%# Container.DataItemIndex %>' runat="server"></asp:LinkButton>

    </ItemTemplate>

    </asp:TemplateField>

    </Columns>

    </asp:GridView>

in .cs file

 protected void gvinsert_RowCommand(object sender, GridViewCommandEventArgs e)

    {

        int index =Convert.ToInt32(e.CommandArgument);

        if (e.CommandName == "recordedit")

        {

            //write your code here

        }

    }

G.Varun

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Posted by: Sksamantaray on: 12/16/2011 [Member] Silver | Points: 25

0	you can have a linkbutton or hyperlink as a template field.Then in gridview's rowdatabound event , you need to find the control and its corresponding datakey value(unique)/unique field value DataBinder.Eval(e.Row.DataItem, "fieldname").ToString().Trim(); then you can pass this value to the target page to fetch appropriate record for updation Thanks, Sanjay Chanti444, if this helps please login to Mark As Answer. \| Alert Moderator

you can have a linkbutton or hyperlink as a template field.Then in gridview's rowdatabound event , you need to find the control and its corresponding datakey value(unique)/unique field value
DataBinder.Eval(e.Row.DataItem, "fieldname").ToString().Trim();
then you can pass this value to the target page to fetch appropriate record for updation

Thanks,
Sanjay

Chanti444, if this helps please login to Mark As Answer. | Alert Moderator

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